math problem cannot comprehend

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thread starter buibuibui Oct 03 2010 + PM | QUOTE | PERMALINK | REPORT

how does f(x)=(x^2) - x + (5/4) Quadratic equation go to standard form? i don't get the steps answer: (x- 1/2)^2 +1 Edit: meant vertex form. Thanks for answers..feeling prettty dumb right now.

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Shine 10/03/10 + PM | QUOTE | PERMALINK | REPORT

Completing the square.

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bboyever 10/03/10 + PM | QUOTE | PERMALINK | REPORT

standard form = standard form. as simple as that. I don't know how else to explain it.

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sleepyxdude + PM | QUOTE | PERMALINK | REPORT

You know how square binomials work, right? (ax+b)^2 = (ax)^2 + 2ab + b^2 or (ax-b)^2 = (ax)^2 - 2ab + b^2 x^2 - x + 5/4 (x^2 - x + 1/4) + 1 (x - 1/2)^2 + 1

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doomzdragonz + PM | QUOTE | PERMALINK | REPORT

You make a perfect square in this function to covert it to standard form. So in this example, x^2 - x part would need a constant to make it a perfect square. In this case you would need to add the constant "1/4", making it x^2 - x + 1/4 + 1. The "x^2 - x + 1/4" would become (x - 1/2)^2 and the entire function should be (x - 1/2)^2 + 1

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tangentline 10/03/10 + PM | QUOTE | PERMALINK | REPORT

If I'm right, that's vertex form (the answer) And it is already in standard form.

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