Homework help! (its math)
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thread starter FunGuyAryand Sep 07 2010 + PM | QUOTE | PERMALINK | REPORT
The question is what's the size of the largest square that can fit within a right triangle whose legs are 12cm and 5cm. please and thanks :D
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Th3Miss 09/07/10 + PM | QUOTE | PERMALINK | REPORT
its difficult. does this help?
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Enliight 09/07/10 + PM | QUOTE | PERMALINK | REPORT
Have you tried drawing it out?
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illkoyou + PM | QUOTE | PERMALINK | REPORT
It's not difficult. Just draw it out and you'll see what I mean. Brb working on it. Edit: May I ask your grade? I don't wanna become too complicated when explaining :o.
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omg299 09/07/10 + PM | QUOTE | PERMALINK | REPORT
i got 16cm wht did you guys get?
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FunGuyAryand 09/07/10 + PM | QUOTE | PERMALINK | REPORT
lol i'm a junior, i'm fairly good at math but for some reason this is difficult -.-
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Ren572 09/07/10 + PM | QUOTE | PERMALINK | REPORT
define size area? perimeter? side lentghs?
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bboyever 09/07/10 + PM | QUOTE | PERMALINK | REPORT
9.6 cm
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illkoyou 09/07/10 + PM | QUOTE | PERMALINK | REPORT
16 I believe. If you draw it out, you'll see that it forms a square and two triangles. From there one, it is assumable that the squares length and width are half the legs of the triangle sides (5 divided by 2 is 2.5, 12 divided by 2 is 6), and to find area, LxW, so 6x2.5, which = 16.
My Characters: xjoethearanx - 100 Scania Aran in Misery
doomzdragonz 09/07/10 + PM | QUOTE | PERMALINK | REPORT
A square with sides of 7.0588 cm.
My Characters: AcemagicianX - 68 Bera I/L Wizard
Ren572 09/07/10 + PM | QUOTE | PERMALINK | REPORT
[quote] illkoyou : 16 I believe. If you draw it out, you'll see that it forms a square and two triangles. From there one, it is assumable that the squares length and width are half the legs of the triangle sides (5 divided by 2 is 2.5, 12 divided by 2 is 6), and to find area, LxW, so 6x2.5, which = 16. [/quote] squares have equal side lengths
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AznKasaKi + PM | QUOTE | PERMALINK | REPORT
[quote] illkoyou : 16 I believe. If you draw it out, you'll see that it forms a square and two triangles. From there one, it is assumable that the squares length and width are half the legs of the triangle sides (5 divided by 2 is 2.5, 12 divided by 2 is 6), and to find area, LxW, so 6x2.5, which = 16. [/quote] Whoops, nevermind
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illkoyou + PM | QUOTE | PERMALINK | REPORT
[quote] Ren572 : squares have equal side lengths [/quote] Oh right..I can't read. My bad. brb again. EDIT: I believe since 2.5 is the max that can be achieved for one side, and square's sides are equal, than 2.5 should be the other. Therefore, 2.5x2.5?
My Characters: xjoethearanx - 100 Scania Aran in Misery
doomzdragonz 09/07/10 + PM | QUOTE | PERMALINK | REPORT
Wait nevermind, the largest square that could fit would have side lengths of 3.529 cm.
My Characters: AcemagicianX - 68 Bera I/L Wizard
arrowarrow + PM | QUOTE | PERMALINK | REPORT
3600/289 Edit: Yeah, basically what above got. Go ahead and explain it to him because it's a pain trying to explain geometry without showing you a picture.
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