Math help please!
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thread starter Gyani Jul 28 2010
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| Well I'm going to grade eight and my mom got me tutor. Well I got a question that I'm a bit confused on (Homework), so could you guys help me out? If your willing, the question is: Johan has a 300-cm ladder that he leans up against a wall. The safety sticker on the side of the ladder shows that the bottom must be placed between 70cm and 110cm away from the wall. What are the minimum distance and maximum distance up the wall that the ladder can reach, Give your answer to the nearest tenth of a centimetre. Thanks! My questions been answered, thank you everyone for helping me out! |
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XcoldshadowX 07/28/10
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| Hint: Think of it as a triangle. |
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Gyani 07/28/10
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| hmm... right triangle.. lemme sketch this out.. |
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blades998 07/28/10
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| I'm starting Gr7 in Sept., so I'll probably be wrong but: minimum = 190 cm. maximum = 230 cm. |
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Gyani 07/28/10
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| eh.. i'm pretty sure you don't subtract it.. |
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Piyohonke 07/28/10
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| You have to use the Pythagorean theorem, of a^2 + b^2 = c^2 Where C = 300 A = 70 or 110 and b = x. So your equations should look like 4900 + b^2 = 90000 and 12100 + b^2 = 90000. Just solve for b. |
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Corbenik 07/28/10
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| And there in lies the use of trignometry. |
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Camdon 07/28/10
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| [quote] Piyohonke : You have to use the Pythagorean theorem, of a^2 + b^2 = c^2 Where C = 300 A = 70 or 110 and b = x. So your equations should look like 4900 + b^2 = 90000 and 12100 + b^2 = 90000. Just solve for b. [/quote] Bingo! Beat me to it |
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Gyani 07/28/10
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| [quote] Piyohonke : You have to use the Pythagorean theorem, of a^2 + b^2 = c^2 Where C = 300 A = 70 or 110 and b = x. So your equations should look like 4900 + b^2 = 90000 and 12100 + b^2 = 90000. Just solve for b. [/quote] Hmm just one question, what ''^" is it subtraction? I know ''*'' is multiplication.. |
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Sadaxer 07/28/10
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| Although the question might seem confusing, remember that they're always linked to whatever you studied before in class or so. And yes, it's a right triangle basically. |
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braadw0rst
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| If your willing, the question is: Johan has a 300-cm ladder that he leans up against a wall. The safety sticker on the side of the ladder shows that the bottom must be placed between 70cm and 110cm away from the wall. What are the minimum distance and maximum distance up the wall that the ladder can reach, Give your answer to the nearest tenth of a centimetre. 300 cm ladder. a�+b�=c�. c�=300� so a�+b�=300�. if b=70 then a�=300�-70� a=sqrt(85 100) = 291.719043 <--- maximum if b=110 then a�=300�-110� a = sqrt(77 900) = 279.105715 <--- minimum |
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2006 07/28/10
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bandducky511 07/28/10
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| Wait a 3 meter ladder? Isn't that a bit small.... OT: "^" means to the power of. So ^2 would be power of 2 meaning you square it or multiply it twice. ^3 would mean power of 3 aka multiplying it 3 times. |
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Gyani 07/28/10
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| [quote] 2006 : ^ = to the power of [/quote] Oh, now it makes sense, thanks! |
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Hakizo 07/28/10
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| Pythagora. I'm too lazy to solve but if you draw it you'll understand. |
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