Math question - BasilMarket Forum

Math question

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thread starter IKEA12311 Sep 11 2009 + PM | QUOTE | PERMALINK | REPORT

(x + y)^2 - x - y how do i factor it luls

Bystander 09/11/09 + PM | QUOTE | PERMALINK | REPORT

You don't. There's no equal sign.

heinous Sep 11 2009 + PM | QUOTE | PERMALINK | REPORT

Bystander : You don't. There's no equal sign. Yeap. Edit:Oh, factoring, lemme see... Forget it, I don't remember how to factor. :|

Travis 09/11/09 + PM | QUOTE | PERMALINK | REPORT

thats not an equation, just put "impossible"

Zaptacious Sep 11 2009 + PM | QUOTE | PERMALINK | REPORT

x^2 + y^2 - x - y or Xy^2 - x -y

XcoldshadowX Sep 11 2009 + PM | QUOTE | PERMALINK | REPORT

Zaptacious : x^2 + y^2 - x - y 1) That would be expanding it 2) Your expansion is incorrect. Zaptacious : or Xy^2 - x -y ROFL! That's even worse.

IKEA12311 09/11/09 + PM | QUOTE | PERMALINK | REPORT

Zaptacious : x^2 + y^2 - x - y (x+y)^2 = x^2 + 2xy + y^2 =/= x^2 + y^2 - x - y

superapple2 09/11/09 + PM | QUOTE | PERMALINK | REPORT

@above you should get an F for expanding (x+y)^2 like that it should really be x^2+xy+yx+y^2

Bystander Sep 11 2009 + PM | QUOTE | PERMALINK | REPORT

Expands to (x^2+2xy+y^2)-x-y. Er. Just factor? Dunno if grouping works here. I got (x+y)(X+y-1)

IKEA12311 Sep 11 2009 + PM | QUOTE | PERMALINK | REPORT

Bystander : Expands to (x^2+2xy+y^2)-x-y. Er. Just factor? Dunno if grouping works here. Can i see your work? D: I messed up doin the steps

YaItsKynic Sep 11 2009 + PM | QUOTE | PERMALINK | REPORT

(x+y)^2 -x -y (x+y)(x+y) - 1(x+y) (x+y)[(x+y) - 1] (x+y)(x+y-1) Bystander is making things more complicated than need be.

Bystander Sep 11 2009 + PM | QUOTE | PERMALINK | REPORT

IKEA12311 : Well i got: x^2 + 2 xy + y^2 - x - y x(x + 2y -1) +y(y-1) (x + y) (x + 2y -1) (y -1) (x+y) (xy -x +2y^2 - 3y + 1)? I used the other dude's equation of x^2+xy+yx+y^2 (x^2+xy-x)+(y^2+yx-y) <-Rearranged to terms to factor them. x(x+y-1)+y(y+x-1) <-Distributive prop. x(x+y-1)+y(x+y-1) <- Rearranged the numbers again (x+y)(x+y-1) <- Distributive prop again. Took a while to write, sorry lol.

IKEA12311 09/11/09 + PM | QUOTE | PERMALINK | REPORT

Bystander : I used the other dude's equation of x^2+xy+yx+y^2 (x^2+xy-x)+(y^2+yx-y) <-Rearranged to terms to factor them. x(x+y-1)+y(y+x-1) <-Distributive prop. x(x+y-1)+y(x+y-1) <- Rearranged the numbers again (x+y)(x+y-1) <- Distributive prop again. Took a while to write, sorry lol. Thanks, that helped a lot. i completely forgot about rearranging the equation x.x

SinghNinja 09/11/09 + PM | QUOTE | PERMALINK | REPORT

dam wat grade math is this ?

YaItsKynic 09/11/09 + PM | QUOTE | PERMALINK | REPORT

IKEA12311 : Thanks, that helped a lot. i completely forgot about rearranging the equation x.x You don't have to square the binomial. You can do the problem without it because there is a like term of (x+y).