an algebra 2 problems i need some smart students to help me
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thread starter linh12345 Oct 16 2010 + PM | QUOTE | PERMALINK | REPORT
6x^2-15x-9=0 thanks guys!
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magaaran 10/16/10 + PM | QUOTE | PERMALINK | REPORT
o.k.. factor it?
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gragon + PM | QUOTE | PERMALINK | REPORT
6x^2-15x-9=0 (6x+3)(x-3)=0 or 6x^2-15x-9=0 3(2x^2-5x-3) 3(2x+1)(x-3)
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123mike9 10/16/10 + PM | QUOTE | PERMALINK | REPORT
6x^2-15x-9=0 (6x+3)(x-3)=0 or 6x^2-15x-9=0 3(2x^2-5x-3) 3(2x+1)(x-3) Your welcome
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linh12345 10/16/10 + PM | QUOTE | PERMALINK | REPORT
thanks you everyone accept for the 1 st commentor
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DarkOdor 10/16/10 + PM | QUOTE | PERMALINK | REPORT
DarkOdorMove the 6 in front of the x^2 to the back and multiply the 6 with -9 Then...just factor it lmao. 1. 6x^2 - 15x- 9 =0 2. x^2 - 15x - 54 = 0 3. (x+3)(x-18) 4. (6x+3)(6x-18) 5. (6x+3)(x-3)
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gragon + PM | QUOTE | PERMALINK | REPORT
I can't honestly say if you did that yourself, or if you copy and pasted mine, but he is right Edit: This is for the guy right under my first post.
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DarkOdor 10/16/10 + PM | QUOTE | PERMALINK | REPORT
DarkOdor[quote] gragon : I can't honestly say if you did that yourself, or if you copy and pasted mine, but he is right [/quote] lol he copy + pasted yours but included in a "Your welcome :D"
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gragon 10/16/10 + PM | QUOTE | PERMALINK | REPORT
@darkodor, can you explain each step inbetween, i can't seem to follow your logic
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ranger2962 + PM | QUOTE | PERMALINK | REPORT
[quote] ranger2962 : 6x^2-15x-9=0 Divide by 3 3(2x^2)-5x-3 Start factoring 3(2x+1)(x-3) Now, if you want the solutions you set (2x+1)=0 (x-3)=0 2x+1=0 x-3=0 2x=-1 x=3 x= -(1/2) X=(-1/2) or 3 [/quote] You can also use the qudratic formula x=(-b+or-radb^2-4ac)/2a x=(15+or-rad225-4(6)(-9))/12 x=(15+or-rad225+216)/12 x=(15+or-21)/12 x=(15+21)/12 x=36/12 x = 3 x=(15-21)/12 x=-6/12 x=-1/2 Once agian x= -1/2 or 3
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SilentXynh 10/16/10 + PM | QUOTE | PERMALINK | REPORT
[quote] linh12345 : thanks you everyone accept for the 1 st commentor [/quote] Technically there's nothing wrong with the first poster's comment. You didn't tell us what you wanted to do? You should specify if you want to solve for x or factorise the equation. Telling us just the equation without any other instructions does not help in any way. OT: Factorise a 3 out, and go from there.
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HaiiOfFame 10/16/10 + PM | QUOTE | PERMALINK | REPORT
1- take graphic calculator ti-83+ 2- plug in the equation 3- trace the graph 4- function: find zeros 5- boss
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Gaga 10/16/10 + PM | QUOTE | PERMALINK | REPORT
6x^2-15x-9= 0 (6x + 3)(x - 3) x = -1/2 or 3.
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crapisgood 10/16/10 + PM | QUOTE | PERMALINK | REPORT
This is algebra 1 btw. Any other questions feel free to ask btw.
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NeoDagger 10/16/10 + PM | QUOTE | PERMALINK | REPORT
You're kidding me right. Doesn't your book have answers?
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