You pro math enough to do this?
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thread starter NightSky May 01 2010
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| Let x be an integer greater or equal than 0 and smaller than 1000000000000000000 (10^18). Let ds(x) be the digit sum of x, i.e. ds(123) = 1 + 2 + 3 = 6 For how many distinct x is ds(x) = ds(137 * x)? Also explain |
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heinous 05/01/10
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 | Sorry. I'm lost. lost in your eyes, that is. |
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Watdoy0uwant 05/01/10
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SlashxD 05/01/10
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| It's definitely the square root of pie. No doubt about it. |
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Ickest 05/01/10
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| [quote] SlashxD : It's definitely the square root of pie. No doubt about it. [/quote] Square root of pi^3* |
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SlashxD 05/01/10
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| [quote] Ickest : Square root of pi^3* [/quote] I spelt it wrong. my bad. |
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Kalemora 05/01/10
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Fearless 05/01/10
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heinous 05/01/10
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 | [quote] SlashxD : I spelt it wrong. my bad. [/quote] It's funny because both of your avatars look exactly the same. But yeah, I still haven't a clue what this is. |
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ClownIzSiick 05/01/10
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cyaltr 05/01/10
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theNorm 05/01/10
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| Lemme get back to you while I work it out. |
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Sjoooberg
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| I don't want to know. I hate math, since 1st grade. |
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Coax 05/01/10
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| x cannot be greater or equal to 9 since 137^x it would exceed 10^18 x^8 is about 1.2409793x10^17 i don't have a calculator that reads up to 20 digits, so i can't do it :| |
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Sparxxors847 05/01/10
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