solve this geometry problem for a cookie

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thread starter k91133 Apr 19 2010 + PM | QUOTE | PERMALINK | REPORT

helllp please :D http://i222.photobucket.com/albums/dd316/k91133/solve.jpg

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deadlyzombie 04/19/10 + PM | QUOTE | PERMALINK | REPORT

66 degrees, do I win?

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k91133 + PM | QUOTE | PERMALINK | REPORT

can you elaborate on that? did you just divide 132 by 2?

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deadlyzombie 04/19/10 + PM | QUOTE | PERMALINK | REPORT

Okay, I'm pretty sure the rule for the angle at the circumference is half of the angle at the centre. I'm not completely sure, so you better hope someone else can elaborate :3

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k91133 04/19/10 + PM | QUOTE | PERMALINK | REPORT

ahhh at 3 am. basil gets deaaad

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deadlyzombie 04/19/10 + PM | QUOTE | PERMALINK | REPORT

http://www.mathsteacher.com.au/year10/ch06_geometry/08_angle_at_centre/circ.htm#anglecentre Explained in this site, go to the theorem section just below.

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KoolkidXD 04/19/10 + PM | QUOTE | PERMALINK | REPORT

[quote] deadlyzombie : Okay, I'm pretty sure the rule for the angle at the circumference is half of the angle at the centre. I'm not completely sure, so you better hope someone else can elaborate :3 [/quote] im pretty sure this is it.

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bandicoot 04/19/10 + PM | QUOTE | PERMALINK | REPORT

66 It's an inscribed angle and that means the degrees given needs to be divided by 2

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jellybby 04/19/10 + PM | QUOTE | PERMALINK | REPORT

angleBAC = 1/2 x 132degrees = 66degrees. reason; angle at circumference = 1/2 angle at centre of circle standing on the same arc.

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