Prove my friend wrong
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thread starter OnePower Apr 15 2010 + PM | QUOTE | PERMALINK | REPORT
My friend showed me his "proof" that 1 = 2. I know it's wrong but he wont believe me -_- Help? 1 = x x^2 = 1 So x = x^2 x - 1 = x^2 - 1 Quadratic x - 1 = ( x - 1)( x +1) Cancel x -1 1 = x + 1 x=1 1 = 1 + 1 1 = 2
shagreenheart + PM | QUOTE | PERMALINK | REPORT
i hate young buck math kids who try to re-invent the wheel. if 1 = 2 then his first equation is laugh-in-his-face wrong. edit to make myself more clear: you can't use 1 with a value of 1 if you're trying to prove the value of 1 = 2. that's utterly moronic.
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OnePower 04/15/10 + PM | QUOTE | PERMALINK | REPORT
: He wants an actual proof though
xFishy 04/15/10 + PM | QUOTE | PERMALINK | REPORT
Cancelling (x - 1) would be dividing by 0, since x = 1
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OnePower 04/15/10 + PM | QUOTE | PERMALINK | REPORT
He says 0/0=1 @.@ Since anything divided by itself is 1
acm180 04/15/10 + PM | QUOTE | PERMALINK | REPORT
Error divide by 0. X-1 / X - 1 = 0/0 = UNDEFINED
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Cyrus0 + PM | QUOTE | PERMALINK | REPORT
[quote] xFishy : Cancelling (x - 1) would be dividing by 0, since x = 1 [/quote] Not necessarily, because you would look at it as " (1) (x-1)=(x+1)(x-1)", in which case, you could cancel out the (x-1)s, and still have the "(1)=(x+1)", seeing as how 1 times a number or quantity wouldn't change it's value. I know there's something wrong with this, I just can't find it :/ @OnePower: No, because even if it was 0 divided by 0, it would still be undefined, seeing as how it was divided by 0, and not 1. Sounds like your friend is just trying to be a smartass.
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ShadeCombo 04/15/10 + PM | QUOTE | PERMALINK | REPORT
1=/=2 We learned that since Pre-School >:O To think that, that rule still is right...
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ranger2962 + PM | QUOTE | PERMALINK | REPORT
[quote] OnePower : He says 0/0=1 @.@ Since anything divided by itself is 1 [/quote] He's an idiot. He should know that 0 is an exception, duh. You can't divide anything by 0.(Including 0)
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zXFight3rzXz + PM | QUOTE | PERMALINK | REPORT
The moment he said 1 = x, you would have to substitute 1 for x. (1)^2 = 1 1 = 1. You're friend is a dumbass. 1 = x is the same as x = 1.
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ranger2962 04/15/10 + PM | QUOTE | PERMALINK | REPORT
We even had this as a question of a day in algebra. Our teacher asked us to tell us why this proof is wrong. It's because x-1=0 And dividing by 0 = a big no no
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Cyrus0 + PM | QUOTE | PERMALINK | REPORT
EDIT: Never mind, forgot that canceling=dividing. Sorry. @TS: Yeah, your friend is full of crap.
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Lifescience 04/15/10 + PM | QUOTE | PERMALINK | REPORT
0/0 is undefined, since it equates to how many zeroes would satisfy an answer of zero. Since there are an infinite number of possibilities, 0/0 would not equal to one.
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xWillcola + PM | QUOTE | PERMALINK | REPORT
If 1=2 then 4=5
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xFishy 04/15/10 + PM | QUOTE | PERMALINK | REPORT
[quote] Cyrus0 : Not necessarily, because you would look at it as " (1) (x-1)=(x+1)(x-1)", in which case, you could cancel out the (x-1)s, and still have the "(1)=(x+1)", seeing as how 1 times a number or quantity wouldn't change it's value. I know there's something wrong with this, I just can't find it :/ @OnePower: No, because even if it was 0 divided by 0, it would still be undefined, seeing as how it was divided by 0, and not 1. Sounds like your friend is just trying to be a smartass. [/quote] I don't quite understand you? But from how I was taught, you'd divide both sides by (x - 1) and end up with 1 = (x + 1), but since x = 1, dividing by (x - 1) equates to dividing by 0. Just want a clarification on that!
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