Are you smarter than a 6th grader?
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thread starter Fearless Jul 30 2009
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| I have been stuck on this problem since 10 o' clock (it's now 11:15). And yes, i am in 6th grade. 5 mill for anyone who can give me the equation/answer (must be in scania) The question : A passenger train travels 60 mph and a freight train travels 40mph. It takes the passanger train 1.5 h less time to cover the same distance as a freight train. how long does it take each train to make a trip? EDIT : Here are some more. (5mill each question) : 2) Hans needs to rent a moving truck. Suppose Company A charges a rate of $40/d and company B charges $60 plus $20/d. How many days, must Hans rent the moving truck to justify company B? 3) May rides her bike the same distance that Leah walks. May rides her bike 10km/h faster than Leah walks. If it takes may 1 h and Leah 3 h, how fast does each travel? |
ScaniaSin 07/30/09
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| As long as it wants it to take. Gosh! |
Fearless 07/30/09
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| ScaniaSin said: "As long as it wants it to take. Gosh!" LOL! My first laugh since the question popped up in my paper. |
wonkaisgood 07/30/09
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| theres not enough information,it doesnt tell how far the trains went |
tkoh 07/30/09
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| wonkaisgood said: "theres not enough information,it doesnt tell how far the trains went" no... there's enough info (1.5 hours) i think. i dunno. It's summer. |
beast1333 07/30/09
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xxSwirl 07/30/09
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| 6th graders are learner harder things, i'm too stupid for this sorry :< |
xxsasuke20xx 07/30/09
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FatelessNexus 07/30/09
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| Let x be the time it takes the passenger train to get to its destination 60x = passenger trains distance covered 40(x+1.5) = freight trains distance covered Since they're equal distances, set the two expressions equal to one another and solve 60x = 40x + 60 20x = 60 x = 3 3 hours for passenger train and 4.5 hours for freight train |
darkballer3 07/30/09
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 | Don't you cross multiply? Maybe not...it's pretty late here :] |
KnightSword 07/30/09
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| im gonna guess its 4.5hrs for the passenger train and 6hr for freight train.Don't use my anwsers there most likely wrong |
tkoh 07/30/09
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| FatelessNexus said: "Let x be the time it takes the passenger train to get to its destination 60x = passenger trains distance covered 40(x+1.5) = freight trains distance covered Since they're equal distances, set the two expressions equal to one another and solve 60x = 40x + 60 20x = 60 x = 3 3 hours for passenger train and 4.5 hours for freight train" Here, have a cookie. |
jaykay244 07/30/09
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| Doesn't it state the answer in the question? |
xiadowstarz 07/30/09
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| This is Algebra lol o.o Something to do with Rate x ___ = Work done or something |
FatelessNexus Jul 30 2009
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| tkoh said: " Here, have a cookie." *takes cookie, munches* ty 2) Hans needs to rent a moving truck. Suppose Company A charges a rate of $40/d and company B charges $60 plus $20/d. How many days, must Hans rent the moving truck to justify company B? Let x = number of days 40x = total amount he has to pay company A 20x + 60 = total amount he has to pay company B Justifying basically is breaking even more or less so set them equal to each other. 20x + 60 = 40x 60 = 20x x = 3 At least 3 days to justify the cost of company B 3) May rides her bike the same distance that Leah walks. May rides her bike 10km/h faster than Leah walks. If it takes may 1 h and Leah 3 h, how fast does each travel? Let x = Leah's walking speed Let x + 10 = May's speed Let 3x = distance Leah travels Let 1(x + 10) = distance May travels They both travel the same distance so you set them equal again. 3x = x +10 2x = 10 x = 5 Leah travels 5 km/hr. May travels 15 km/hr |
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