Quick Algebra II Question!

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thread starter by6000 Jul 01 2009 + PM | QUOTE | PERMALINK | REPORT

How to do you solve the following used a logarithmic function (ln x or y = ln x)? 1.3^x = 8 Solving for x using logarithmic function... anyone know? If so please explain, don't just give me the answer. Thanks!

Coax 07/01/09 + PM | QUOTE | PERMALINK | REPORT

Bystander said: " Fort this one you can make the base the same. 2^(5/3) x (2^2)^(2/3), so it's 2^(5/3) x 2^(4/3). Rest is easy." yoshidude65 said: " You can change the base (i.e. 2 = 4^1/2 or 4 = 2^2)" thanks, both of you

Gofsodon 07/01/09 + PM | QUOTE | PERMALINK | REPORT

lotus said: "btw, it's 'log' not 'ln' natural log is used with euler's number.." You can still use ln. "ln" is simply "log" with base "e". The rules for logs still apply.

Avatar 07/01/09 + PM | QUOTE | PERMALINK | REPORT

why do you guys use wierd symbols you confuse me what happened to X,+, -, is my school the only school that uses these =[

Gofsodon 07/01/09 + PM | QUOTE | PERMALINK | REPORT

Avatar said: "why do you guys use wierd symbols you confuse me what happened to X,+, -, is my school the only school that uses these =[" o_o People still use + and -. But the use of "x" as a multiplication sign can be confused for the variable "x", so we just put numbers in brackets. Like, 3 times 4 would be 3(4). As for log and ln, those are basically exponents. I'm not sure if you learned them yet or not. o-o

Bystander 07/01/09 + PM | QUOTE | PERMALINK | REPORT

Avatar said: "why do you guys use wierd symbols you confuse me what happened to X,+, -, is my school the only school that uses these =[" It's preferable to use * to mean multiplication for the person above's reasons.