Math question - BasilMarket Forum

Math question

basilmarket.com forums : Chat | 9 posts archived

thread starter Zyphlo Jun 30 2009 + PM | QUOTE | PERMALINK | REPORT

2sin2x = tan x Can someone guide me through that?

Andromeda 06/30/09 + PM | QUOTE | PERMALINK | REPORT

i hate trig.

Cloat 06/30/09 + PM | QUOTE | PERMALINK | REPORT

i hate trig.

benq Jun 30 2009 + PM | QUOTE | PERMALINK | REPORT

Done.

Zyphlo 06/30/09 + PM | QUOTE | PERMALINK | REPORT

please can someone help me? I have class in half an hour and I have many more of these knds of questins to do

Simford 06/30/09 + PM | QUOTE | PERMALINK | REPORT

if i learned past math 9 i would help you

LimusocoBobo 06/30/09 + PM | QUOTE | PERMALINK | REPORT

2sin(2x) = tan(x) 2sin(2x) = sin(x)/cos(x) 2sin(2x)cos(x) = sin(x) (2sin(2x)cos(x))/sin(x) = 1 (2sin(2x)cos(x))/sin(x) = sin^2(x) + cos^2(x) Maybe that's a starting point. See where you can go from there.

FD17 06/30/09 + PM | QUOTE | PERMALINK | REPORT

LimusocoBobo said: "2sin(2x) = tan(x) 2sin(2x) = sin(x)/cos(x) 2sin(2x)cos(x) = sin(x) (2sin(2x)cos(x))/sin(x) = 1 (2sin(2x)cos(x))/sin(x) = sin^2(x) + cos^2(x) Maybe that's a starting point. See where you can go from there." I just finished trigonomatry and i have no clue what you did lol

Gofsodon Jun 30 2009 + PM | QUOTE | PERMALINK | REPORT

2sin2x = tan x We know that sin2x = 2sinxcosx Thus: 2(2sinxcosx) = tanx 4sinxcosx = tanx We know that tanx = sinx / cosx. 4sinxcosx = sinx / cosx Divide both sides by sinx. 4cosx = 1/cosx Multiply both sides by cosx. 4cos squared x = 1 Let cosx = a. 4a^2 = 1 a^2 = 1/4 a = 1/2 or -1/2 cosx = 1/2 or -1/2 You can do the rest (use special triangle with sides 1, 2, and square root 3).