Need help with math
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thread starter one23abc Jun 20 2009
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| Ok this is the question: A basketball team of 5 people is selected from 11. 3 are centers, 4 are guards, and 4 are fowards. If the team of 5 needs at least 2 guards, 1 center, and 1 foward, then how many different combinations of team members are there? |
ICantKs 06/20/09
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| I think there's 49 or 50. |
megaf6 06/20/09
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yoshidude65 06/20/09
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| There are a couple ways to do this. The easiest is probably this: Take the total combinations and subtract off the ones that violate your condition. So: All combinations = C(11,5) Then subtract the cases with 0 and 1 guards, the case with 0 centers (so there are 8 people left, so it's C(8,5)), and the case with 0 forwards (there would be 7 people left to choose from, so it is C(7,5)). That should be a good start. |
ISeeDeath Jun 20 2009
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 | If I did the math right 504. |
theory 06/20/09
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| use the combination function on the calculator that's how I do it lol too lazy to memorize the actual equation.. |
one23abc 06/20/09
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| I know the answer (its 228, i checked in the back of the book) but I don't know how to get to it! |
hoopsdood32 Jun 20 2009
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| If different orders count as different combinations, 672. EDIT: 768, forgot something |
one23abc 06/20/09
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| hoopsdood32 said: "If different orders count as different combinations, 672." Different orders arn't counted. |
hoopsdood32 Jun 20 2009
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| one23abc said: " Different orders arn't counted." K, lemme think again, while my calc is 2 steps away xD EDIT: Its 228 then, I think. |
one23abc 06/20/09
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| hoopsdood32 said: " K, lemme think again, while my calc is 2 steps away xD EDIT: Its 228 then, I think." Er.. Can you tell me how you did it?> |
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