More math 12 help probability!
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thread starter h0bob01 May 29 2009
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| Two hockey players, Tom and Jerry, each shoot a penalty shot at a goal. Tom has a 1/2 chance of scoring and Jerry as a 2/5 chance of scoring. Assuming independence, what is the probability that at least one of them will score a goal? Thank you! |
tomvrinzen 05/29/09
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 | 1/2*3/5+1/2*2/5+1/2*2/5 if i recall correctly |
h0bob01 05/29/09
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| Is it P(tom wins, jerry loses + tom loses, jerry wins + prob both win)? |
tomvrinzen May 29 2009
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 | my explanation to up top + P(atleast one wins)TomWins+JerryWins+BothWin |
Userious 05/29/09
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| sorry i am really sleepy and i haven't touch probabily for 5 years ..... but ... ... anyway it might be wrong... 1 - (1/2*3/5) |
ipwnzjoo34 05/29/09
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| 1/5? I can't remember if I'm doing it right... |
h0bob01 May 29 2009
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| tomvrinzen was right, it's 7/10. Thanks man! |
InBrunei 05/29/09
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| I may learn this later in the year. |
tomvrinzen 05/29/09
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 | I had my math final exam last week of course I am right ;) |
Userious 05/29/09
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| h0bob01 said: "tomvrinzen was right, it's 7/10" lol my answer is right too.... my is more simple idea though... it's 100% - (% of they both fail) |
braadw0rst 05/29/09
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| I'm not sure but i'll try anyway 1 - P( none of them scores ) = 1 - (1/2*3/5) I don't know how to explain this in english, cuz i'm dutch but i've used the complement rule xD It says atleast 1 of them scores, = equal to 1 - none scores |
hello12341 05/29/09
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| isnt it just 1/2*2/5? =1/5 |
h0bob01 05/29/09
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| ahh, yes. that way works too. |
Userious May 29 2009
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| braadw0rst said: "I'm not sure but i'll try anyway 1 - P( none of them scores ) = 1 - (1/2*3/5) I don't know how to explain this in english, cuz i'm dutch but i've used the complement rule xD It says atleast 1 of them scores, = equal to 1 - none scores" you did the same method as me and you explain much much better than i did EDIT: alright... 4:25 AM and i still have things to do.... peace... |
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